BIT FIELDS

Suppose your C program contains a number of TRUE/FALSE variables grouped in a structure called status, as follows:

struct
{
 unsigned int widthValidated;
 unsigned int heightValidated;
} status;        
        

This structure requires 8 bytes of memory space but in actual, we are going to store either 0 or 1 in each of the variables. The C programming language offers a better way to utilize the memory space in such situations. If you are using such variables inside a structure, then you can define the width of a variable which tells the C compiler that you are going to use only those number of bytes. For example, the above structure can be rewritten as follows:

struct
{
 unsigned int widthValidated : 1;
 unsigned int heightValidated : 1;
} status;        
        

The above structure requires 4 bytes of memory space for status variable, but only 2 bits will be used to store the values. If you will use up to 32 variables, each one with a width of 1 bit, then also the status structure will use 4 bytes. However, as soon as you have 33 variables, it will allocate the next slot of the memory and it will start using 8 bytes. Let us check the following example to understand the concept:

#include <stdio.h>
#include <string.h>
/* define simple structure */
struct
{
 unsigned int widthValidated;
  unsigned int heightValidated;
} status1;
/* define a structure with bit fields */
struct
{
 unsigned int widthValidated : 1;
 unsigned int heightValidated : 1;
} status2;
int main( )
{
 printf( "Memory size occupied by status1 : %d\n", sizeof(status1));
 printf( "Memory size occupied by status2 : %d\n", sizeof(status2));
 return 0;
}

        

When the above code is compiled and executed, it produces the following result:

Memory size occupied by status1 : 8
Memory size occupied by status2 : 4        
        

Bit Field Declaration

The declaration of a bit-field has the following form inside a structure:

struct
{
 type [member_name] : width ;
};        
        

The following table describes the variable elements of a bit field:

The variables defined with a predefined width are called bit fields. A bit field can hold more than a single bit; for example, if you need a variable to store a value from 0 to 7, then you can define a bit-field with a width of 3 bits as follows:

struct
{
 unsigned int age : 3;
} Age;
    
    

The above structure definition instructs the C compiler that the age variable is going to use only 3 bits to store the value. If you try to use more than 3 bits, then it will not allow you to do so. Let us try the following example:

#include <stdio.h>
#include <string.h>
struct
{
 unsigned int age : 3;
} Age;
int main( )
{
 Age.age = 4;
 printf( "Sizeof( Age ) : %d\n", sizeof(Age) );
 printf( "Age.age : %d\n", Age.age );
 Age.age = 7;
 printf( "Age.age : %d\n", Age.age );
 Age.age = 8;
  printf( "Age.age : %d\n", Age.age );
 return 0;
}

    

When the above code is compiled, it will compile with a warning and when executed, it produces the following result:

Sizeof( Age ) : 4
Age.age : 4
Age.age : 7
Age.age : 0    
    
ElementsDescription
typeAn integer type that determines how a bit-field's value is interpreted. The type may be int, signed int, or unsigned int.
member_name TThe name of the bit-field.
widthThe number of bits in the bit-field. The width must be less than or equal to the bit width of the specified type.